f (x) = x2 - 7x + 10?

Question

find (a) f (0), (b) f (5), and (c) f (-2).

Answer 1

(a) 0 - 0 + 10 = 10
(b) 25 -35 +10 = 0
(c) 4 + 14 + 10 = 28

Answer 2

a) 0 - 0 + 10 = 10
(b) 25 -35 +10 = 0
(c) 4 + 14 + 10 = 28

Answer 3

a.) f(0) = 0^2 -7*0 +10 = 10
b.) f(5) = 5^2 -7*5 + 10 = 25 -35 +10 = 0
c.) f(-2) = (-2)^2 -7*(-2) + 10 = 4 +14 +10 = 28

Answer 4

Do you mean > f(x) = x^2 - 7x + 10? in which x is raised to the power of 2...

First: replace the given number with the x-variable in the function...

a. replace "0" with the x-variable
f(0) = 0^2 - 7(0) + 10
f(0) = 0 - 0 + 10
f(0) = 0 + 10
f(0) = 10

b. replace 5 with the x-variable...
f(5) = 5^5 - 7(5) + 10
f(5) = 25 - 35 + 10
f(5) = -10 + 10
f(5) = 0

c. replace -2 with the x-variable...
f(-2) = (-2)^2 - 7(-2) + 10
f(-2) = 4 + 14 + 10
f(-2) = 18 + 10
f(-2) = 28

Answer 5

a)f(0)=(0)^2-7(0)+10=
10

b)f(5)=(5)^2-7(5)+10
25-35+10
-10+10=0

c)f(-2)=(-2)^2-7(-2)+10=
4+14+10=28

I hope this helps!
All you do is plug in the numbers for x.

Answer 6

it is f(10) so x could correspond to ten in the ordered pairs (ie the 1st one) f(10) = 10² - 7*10 + 9 (replace x with 10) f(10) = one hundred - 70 + 9 = 39 so the ordered pair is: (10,39)