R = 3S
R+6=2(S+6)
3S+6 = 2S+12
S=6
R = 18
2007-01-12 07:32:29
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answer #1
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answered by bequalming 5
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The equation for solving this problem is:
Let R = Ralph's age. Then
R + 6 = 2(R/3 + 6)
2007-01-12 07:51:45
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answer #2
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answered by Helmut 7
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R = ralph's age
S = sara's age
ralph is 3 times older than sara
R = 3*S
In six years ralph will be twice as old as sara
R+6 = 2*(S+6)
try not to fail your test
2007-01-12 07:35:42
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answer #3
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answered by maatweeb 2
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Ralph age is x:
3*y= x
2*(y+6) = x+6
2*y+2*6 =3*y+6
6=y;
And x = 18
2007-01-12 07:32:45
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answer #4
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answered by Luis U 2
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R - Ralph S-Sara
R=3*S
R+6 = 2(S+6)
2007-01-12 07:41:51
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answer #5
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answered by raf67ab 2
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18 of course
sara is 6 ralph is 18
in 6 years
sara is 12 ralph is 24
2007-01-12 07:37:19
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answer #6
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answered by daanzig 4
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R = 3S
R + 6 = 2(S + 6)
R + 6 = 2S + 12
R = 2S + 6
3S = 2S + 6
S = 6
R = 18
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Ralph is 18 and Sara is 6
In 6 years, Ralph will be 24 and Sara will be 12
2007-01-12 07:32:49
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answer #7
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answered by Tom :: Athier than Thou 6
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r=3s
r+6=2(s+6) substitute r=3s
3s+6=2s+12 subtract s+6 from each side
s=6
sarah is 6 & ralph is 18
2007-01-12 07:44:26
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answer #8
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answered by yupchagee 7
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x=sara's age
3x=ralph's
3x+6=2(x+6)
2007-01-12 07:33:02
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answer #9
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answered by Anonymous
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(R+6)=2*(R/3 + 6)
Solve for R.
2007-01-12 07:34:45
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answer #10
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answered by Anonymous
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