The first side of a triangle measures 5 in. less than the second side, the third side is 3 in. more than the first side, and the perimeter is 17 in. How long is the third side?
2007-01-12 07:21:54 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
second side = x
x-5+x+(x-5)+3 =17
3x=17+7;
x= 24/3=8
first side = 8-5 =3;
third side =8-5+3=6
2007-01-12 07:25:05 · answer #1 · answered by Luis U 2 · 0⤊ 0⤋
First side = 3"
Second side = 8"
Third side = 6"
Perimeter is 17"
2007-01-12 15:33:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
a + b + c = 17
a = b - 5
c = a + 3
c = b - 5 + 3 = b - 2 { Substitute for a }
(b - 5) + b + (b - 2) = 17 { Subsitute for a and c and solve }
3b - 7 = 17
3b = 24
b = 8
a = 3
c = 6 <== This is the third side. QED
2007-01-12 15:25:36 · answer #3 · answered by Dave 6 · 0⤊ 0⤋
The 3rd side is 6 in
if you assume the 2nd side is x,
then the 1st side is x-5
the 3rd side is x-5+3
since the perimeter is 17,
(x-5)+x+(x-5+3)=17
when you solve, x=8
therefore, 3rd side is (8-5+3) = 6 in
2007-01-12 15:36:06 · answer #4 · answered by obeahwoman 1 · 0⤊ 0⤋
6 inches
2007-01-12 15:25:41 · answer #5 · answered by toneland 2 · 0⤊ 0⤋