Joe's age is 4 less than twice the age of his brother Tom. The sum of their ages is 41 years. How old is Joe?

Answer 1

When solving algebraic word problems, we usually assign the variable to the standard of comparison. In this case, the standard of comparison is the age of Tom, so

Let x = Tom's age. Then

"4 less than twice the age of Tom" translates to 2x - 4.

The sum of their ages is 41, so

x + 2x - 4 = 41

Simplifying,

3x - 4 = 41
3x = 45
x = 15

Therefore, Tom is 15, Joe is 2(15) - 4 = 26.

Answer 2

enable Joe's age be x. enable Tom's age be y. x=2y-4 x+y=40-one we've 2 equations only from translating words into math. when you consider that we've 2 variables and a pair of equations, it is remedy-able. when you consider that x = 2y-4, we are able to interchange those words because they are equivalent. in the x + y = 40-one equation, we replace x with 2y-4 simply by the undeniable fact that's an same as x. We get 2y-4+y=40-one. it is 3y=40 5. y=15. x=2y-4 is given. x=2(15)-4=26. Joe is 26. Tom is 15.

Answer 3

Tom's age = t
Joe's age = 2t -4

t + 2t - 4 = 41
3t -4 +4 = 41+4
3t = 45
3t/3 = 45/3
t=15
2 (15) -4 = 30-4 = 26

Answer 4

Equations: J = 2T - 4 and J + T = 41

First: replace 2T - 4 with the "j" variable in the 2nd equation...

2T - 4 + T = 41
3T - 4 = 41

Sec: add 4 to both sidess (opposite side means the opposite sign)...

3T - 4 + 4 = 41 + 4
3T = 45

Third: solve for "T" by isolating it on one side > divide both sides by 3...

3T/3 = 45/3
T = 45/3

Fourth: replace 45/3 with "T" in the 1st equation...

J = 2(45/3) - 4
J = 90/3 - 4
J = 30 - 4
J = 26 yrs old

Answer 5

tom's age = x
Joe's age = 2x-4

equation
x + 2x-4=41

simplify
3x=45
x=15

Joe is 2*15-4=26 years old.

Answer 6

TOM'S AGE= X
JOE'S AGE= 2X-4

3X-4=41
3X=45
X=15

TOM IS 15
JOE IS 26

Answer 7

uh 20??