The sum of three consecutive odd integers is 1,509. What are the integers?

Answer 1

Let

x = the first integer

x + 2 = The second integer

x + 4 = The third integer

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x + x + 2 + x + 4 = 1509

3x + 6 = 1509

3x + 6 - 6 = 1509 - 6

3x = 1503

3x /3 = 1503 / 3

x = 501

The answer is: 501

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The first integer x = 501

The second integer x + 2 = 501+ 2 = 503

The third x + 4 = 501 + 4 = 505

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Answer 2

Let the smallest/first number = x
So the other numbers are x+2 and x+4. Now, the sum of the numbers are as below:
x + x+2 + x+4 = 1509
3x + 6 = 1509;
3x = 1509 - 6 = 1503. So,
x = 1503/3 = 501. Therefore the first number is 501.
Other numbers are 503 and 505. That's all. I guess this is clear to you. All the best. = gsmani9 =

Answer 3

501 503 505 cos u just divide 1509 by 3, and then experiment with all the consecutive odd numbers that involve 503 (1509/3). So you get 499,501,503 OR 501,503,505, OR 503,505,507, and sure enough if u add them up, only 501+503+505 gives 1509 so theyre the answer

Answer 4

i'd not use an equation. i might want to assert "The sum of any 3 abnormal integers will be abnormal, so there aren't any recommendations." If it changed into consecutive even integers, i might want to probable use the equation 2x + 2(x+a million) + 2(x+2) = seventy 2 however the equation x + (x + 2) + (x + 4) = seventy 2 might want to also be valid. (really i might want to probable basically say "the common is seventy 2/3 = 24, so the integers must be 22, 24 and 26.")

Answer 5

assume the three integers are :

n-2 , n , n+2

hence,

n-2 + n + n+2 = 1,509

3n = 1,509

n = 503

therefore, the three integers are :

503-2 , 503 , 503+2

501 , 503 , 505

Answer 6

501, 503, 505

Answer 7

501, 503, 505

Answer 8

Sorry to all the people answering above, but the easiest solution is:

(x-2) + x + (x+2) = 1509.

3x = 1509

x = 503

x-2 = 501
x+2 = 505

Answer 9

x
x+2
x+4

x+x+2+x+4=1509
3x+6=1509
3x=1503
x=501

501, 503 and 505

Answer 10

501,503 and 505