Find 4 consecutive even integers whose sum is 140.?

Answer 1

32,34,36,38

Answer 2

Let x = the first consecutive even integer. It follows that the three following would be: x + 2, x + 4, x + 6.

Since all of these integers must add up to 140, then

x + (x + 2) + (x + 4) + (x + 6) = 140

Group like-terms,

4x + 12 = 140
4x = 128
x = 32

Therefore, the four even integers are:
32, 34, 36, 38

Answer 3

let

x = the first integer

x + 2 = The second integer

x + 4 = The third integer

x + 6 = The fourth integer

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x + x + 2 + x + 4 + x + 6 = 140

4x + 12 = 140

4x + 12 - 12 = 140 - 12

4x = 128

4x /4 = 128 / 4

x = 32

The answer is : The first integer is 32

First integer x = 32

Second integer x + 2 = 32 + 2 = 34

third integer x + 4 = 32 + 4 = 36

fourth integer x + 6 = 32 + 6 = 38
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The integer are

32, 34, 36 and 38

- - - - - - - - -s-

Answer 4

Let x be the first even integer.

Then x+2, x+4, and x+6 must be the next three even integers in succession.

x + (x+2) + (x+4) + (x+6) = 140

4x + 12 = 140
4x = 128
x = 32

That means x+2=34, x+4=36, and x+6=38

Your four consecutive even integers are thus 32, 34, 36, and 38.

32 + 34 + 36 + 38 = 140

Answer 5

A good method is to name one of the integers. It doesn't matter which, so let's call the smallest one n. The next one will be n+2, then n+4, and finally n+6.

Their sum is n+ (n+2) + (n+4) + (n+6) = 4n+12. On the other hand, we're given that the sum is 140, se we get the equation

4n+12=140
4n = 128
n=32

Once we know that the smallest is 32, we can reconstruct the other three numbers: 34, 36, 38.

Answer 6

Here's how to do it.
Divide 140 by 4, that gives you 35. So the average for each number has to be 35. The logical choices then will be 32, 34, 36, and 38, since these are the four around 35 and add up to 140.

Answer 7

assume the integers as "x, x+2, x+4, x+6"
now,
x+x+2+x+4+x+6 = 140
4x + 12 = 140
4x = 140 - 12
4x = 128
x = 128/4 = 32

Answer 8

32, 34, 36, 38

Answer 9

x
x+2
x+4
x+6

x+x+2+x+4+x+6=140
4x+12=140
4x= 128
x=32

32,34,36, and 38

Answer 10

x+ (x+2)+ (x+4)+(x+6) =140

4x =128

x=32

32,34,36,38

Answer 11

x+(x+2)+(x+4)+(x+6)=140
4x+12=140
4x=128
x=32

32,34,36,38