Using the product & quotient rules for negitive numbers
2^3 - 2
________
10^-3 7^-2
2007-01-12 05:18:04 · 10 answers · asked by Ken H 1 in Science & Mathematics ➔ Mathematics
Solve...
x=(8-2)/((1/3^3)*(1/7^2))
x=6/(1/1000)*(1/49)
x=6/(1/49000)
x=6*49000
x=294000
2007-01-12 05:24:39 · answer #1 · answered by runlolarun 4 · 0⤊ 1⤋
(2^3 - 2) / (10^-3)(7^-2)
First realize that 1/a^-n = a^n For the move the denominator to the numerator since both parts are negitive powers.
(2^3 - 2)(10^3)(7^2)
Now just simplify
(8-2)(1000)(49)
(6)(49000)
294,000
2007-01-12 19:20:40 · answer #2 · answered by danjlil_43515 4 · 0⤊ 0⤋
The result is 294000. Here's how:
2^3 - 2 = 6. So [2^3 - 2] / [10^-3 7^-2] = 6*10^3 7^2 = 6*49*1000
= 294000.
USEFUL TIP : Where possible, avoid "Tower of Babel" fractions: a/b/c, e/f/g/h. ...
Live long and prosper
2007-01-12 13:26:28 · answer #3 · answered by Dr Spock 6 · 0⤊ 0⤋
You're missing an operator between 10^-3 and 7^-2, maybe a multiplication?
It's unsolvable without it.
The numerator = 8-2 = 6
If you mean to multiply the denominator, the answer is 294,000.
2007-01-12 13:24:44 · answer #4 · answered by mktgurl 4 · 0⤊ 0⤋
You mean simplify it?
(2^3 - 2)/(10^-3 x 7^-2)
(8 - 2)/[(1/10³)(1/7²)]
6/(1/49000)
294000
2007-01-12 13:24:56 · answer #5 · answered by computerguy103 6 · 0⤊ 0⤋
2^3 - 2 = 2 x 2 x 2 - 2 = 8 - 2 = 6
10^-3 (x) 7^ -2 = 10^(1/3) x 7^(1/2) =
= 2,154 x 2,646 = 5,7
6/5,7 = 1,05
2007-01-12 13:50:12 · answer #6 · answered by robertonereo 4 · 0⤊ 0⤋
2^3 - 2
________
10^-3 7^-2
= (8-6)* 10^3*7^2
= 2*49*10^3
= 98,000
2007-01-12 13:25:40 · answer #7 · answered by ironduke8159 7 · 0⤊ 0⤋
Who knows? I hate math anyways.
2007-01-12 13:22:53 · answer #8 · answered by Beefman 3 · 0⤊ 2⤋
2^3-2=
8-2=6
_____________
10^-37^-2=
(1/10^3)*(1/7^2)=
(1/1000)*(1/49)=
1/(1000*49)=
1/49000
2007-01-12 13:25:03 · answer #9 · answered by Bill 1 · 0⤊ 0⤋
what the ****?? ummm........... nope sorry
2007-01-12 13:21:28 · answer #10 · answered by spicyllama16 1 · 0⤊ 2⤋