How do you solve this problem..step..by..step plz
Multiply.
3y^2 - y - 5
2y
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2007-01-12 04:20:50 · 6 answers · asked by James A 1 in Science & Mathematics ➔ Mathematics
(3y² - y - 5) (2y)
this is of the form a(b+c+d) = ab + ac + ad
2y(3y²) + 2y (-y) + 2y (-5)
6y³ - 2y² - 10y
2007-01-12 04:25:49 · answer #1 · answered by bequalming 5 · 0⤊ 0⤋
So you want to multiply 3y^2 - y - 5 with 2y? To do so, all you have to do is distribution.
2y(3y^2 - y - 5) = 6y^3 - 2y^2 - 10y
2007-01-12 04:24:14 · answer #2 · answered by Puggy 7 · 0⤊ 0⤋
You must multiply 2y times eac term in 3y^2 -y -5
So (2y)(3y^2) - (2y)(y) - (2y)(5)
= 6y^3 -2y^2 -10y
Remember that y^m * y^n = y^(m+n),
so y * y^2 = y^1 * y^2 = y^(1+2) = y^3
2007-01-12 04:34:17 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
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2016-10-30 22:20:09 · answer #4 · answered by ? 4 · 0⤊ 0⤋
* everything by 2y
2y*(3y^2-y-5)=6y^3-2y^2-10y
2007-01-12 04:26:29 · answer #5 · answered by trevelan7 2 · 0⤊ 0⤋
i emailed you did ya get it?
2007-01-12 04:48:18 · answer #6 · answered by Anonymous · 0⤊ 0⤋