Can u solve an inequality? 5x+8 > 7x+8
2007-01-12 04:00:48 · 8 answers · asked by Issa 1 in Education & Reference ➔ Homework Help
5X + 8 > 7x + 8
Subtract 8 from each side to get
5X > 7X
Something tells me you may have copied this down wrong, since the answer to this is "any negative number." The answer doesn't really make much sense.
2007-01-12 04:04:23 · answer #1 · answered by Anonymous · 4⤊ 1⤋
5x+8>7x+8 <=>
5x>7x <=>
-2x>0 <=>
2x<0 <=>
x<0
2007-01-12 12:12:02 · answer #2 · answered by suzanna_banana 4 · 3⤊ 1⤋
Yes, when dealing with greater/less thans, to solve them, replace with an equal sign.
So now you have 5x+8 = 7x+8
Now you want to have the x's isolated, so subtract the 5x from both sides...
Now it's 8 = 2x+8
Subtract the 8 from both sides, so now you have
0 = 2x, divide the 2, making it
0 = x
Now replace back the sign, but since we divided, its now a less than sign
0 < x
x is anything less than 0!! All the negatives!!!
2007-01-12 13:30:10 · answer #3 · answered by toonlink 5 · 1⤊ 1⤋
Not difficult. First subtract 8 from both sides to get
5x > 7x
Now subtract 5x from both sides:
0 > 2x
Reverse the inequality: 2x < 0.
Divide by 2: x < 0.
2007-01-12 13:11:22 · answer #4 · answered by steiner1745 7 · 0⤊ 1⤋
5x+8 > 7x+8
------> 5x > 7x
-------> 0> 2x
--------> 0> x
the answer is any negative number.
2007-01-12 12:10:49 · answer #5 · answered by tedmcju 1 · 3⤊ 0⤋
well if you subtract 8 from both sides, then 5x is greater then 7x..................does not make any sense. Never had a problem like that before
2007-01-12 12:10:46 · answer #6 · answered by james w 3 · 1⤊ 1⤋
5x+8>7x+8
5x-7x>8-8
-2x>0
-2x/-2<0/-2
x<0
2007-01-12 12:58:23 · answer #7 · answered by Bill 1 · 1⤊ 0⤋
5x+8>7x+8
5x>7x
0>7x-5x
0>2x
0>x
2007-01-13 08:05:49 · answer #8 · answered by Praveena 2 · 0⤊ 1⤋