If Gravity produces weight that hold us to the earth?

Question

Does centrifical force of the earths rotation make us lighter at the same time? I've always wondered.

Thanks all for taking the time to answer!

Answer 1

You bet!
The radius of Earth is about 6,400km.
Note: The computation below are for the equator, at the poles the is no centripial force.
The earth rotates at speed of S/t
so circumference S is
S=2piR
T=24hours
V=2(pi)R/24= 1,675 km/h. (1,675,516 m/h)
or
V= 465m/s
The a centripetal =Ac=
Ac=V^2/R
Ac=(465)^2/(6,400,000)= 0.0338m/s^2
The gravitational acceleration g is
g=9.81 m/s^2

The total force is the product of a difference between Ac (upward) and g (downward) times our mass.

Now we can see why we are not flying away into the space. The centripetal acceleration is much too small.

I hope it helps.

Answer 2

Suppose an object is having a speed of 8000 m/s, then the speed is called orbital speed.

With this speed, the object will move round the earth’s surface in a circular orbit i.e., with out pressing the earth’s surface.

When the speed is increased, the radius of the circular path will increase.

When the speed is decreased the radius of the circular path will decrease.

Imagine the earth rotates with a speed of 8000 m/s, then all objects will not press the earth’s surface and the weight will be zero.

But at the equator the speed of earth’s rotation is only 465m/s, not enough to make the weight zero.

All objects press the earth i.e., they show weight.

If the speed were zero, then the weight will have its full strength, the true weight, which is at the poles of the earth.

At the poles there is no linear speed.

Answer 3

Yes, centrifugal force does make us lighter than we'd be without it. However, the constant g = 32.2 ft/sec^2 or 9.81 m/sec^2 was experimentally derived and includes the lightening effect of centrifugal force. Let's look at why:

f = mg = W; f is the net force on a mass (m) due to gravity having a measured acceleration factor (g). It's this net force that we call weight (W), f = mg = W = G - F = ma - mv^2/R = m(a - v^2/R) = m(a - (w^2)R) = m(a - c) = mg; so that g = a - c, where g is that measured constant, a is the acceleration due to gravity that yields a gross weight G, and c is the centrifugal acceleration (v^2/R) at the Earth's radius of spin (R).

w = angular velocity of the Earth's spin = constant; so that (w^2)R = c the acceleration for a constant w. As R --> 0 towards the poles, we see that c --> 0 as well. Thus g = a when measured at the poles because there is no offsetting centrifugal force at these centers of spin. In other words, the value of g depends on where it was measured on Earth.

Answer 4

Weight is the term scientists use to describe how much force due to gravity acts on an object. The amount something weighs depends on two things, how much mass the object has, and how strong the force of gravity is where the object is at.

Mass is a term that describes how much of an object there is. Every atom has a certain mass, and the more atoms there are, the more mass an object has. Every physical object has mass, and this mass is the same no matter where it is.

Gravity is a force that pulls on things. Just like if you push something across the table, your push is a force. There are many different types of forces, but forces are not physical objects, they are more like actions. Since forces are not objects, they do not have mass.

How much something weighs is determined by multiplying the mass of the object by the force of gravity acting on the object.
Forces have no mass, so they never weigh anything. Things that don't have mass, that arent' made up of atoms, don't weigh anything. Also, objects in space don't weigh anything because there isn't any gravity. So, even if an object is very large, if there isn't any gravity, it doesn't weigh anything.

Answer 5

Because the earth is rotating, objects on the earth's surface experience a small centrifugal force, which increases as you get nearer to the equator. This offsets the force of gravity slightly, resulting in a small decrease in the net downward force, and a corresponding small decrease weight.

HTH

Charles

Answer 6

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Answer 7

I think centrifical force keeps things orbitting, so it shouldn't effect your weight.

Answer 8

no, not to any noticable amount.
id imagine it'd be pretty impossible to get near the (non-rotating) poles without help if you actually got that much heavier.

but then again, i really do understand where your coming from!

Answer 9

No.