q^2-q
-----------
q
2007-01-12 01:56:48 · 6 answers · asked by nomansland 2 in Science & Mathematics ➔ Mathematics
didnt mean ? mark
2007-01-12 01:57:12 · update #1
dang, i'm not sure if that's q^(2-q) in the numerator or (q^2) - q
if the latter then factor out a q => [q * (q-1)] / q => q-1
if the former then subtract the denominators exponent from the numerator's exponent
2007-01-12 02:05:21 · answer #1 · answered by gggjoob 5 · 0⤊ 0⤋
Factor out a q and you will have:
q(q-1) / q
Solve the problem by dividing the numberator by q:
ANSWER: q-1
2007-01-12 09:59:30 · answer #2 · answered by aficionado210 2 · 0⤊ 0⤋
(q^2 - q)/q
= q(q - 1) / q (After factorising the numerator)
Now after cancelling both 'q' in numerator and denominator, we get (q - 1) and this is the answer. I guess it is clear to you.
All the best. =gsmani9=
2007-01-12 10:18:58 · answer #3 · answered by mani 2 · 0⤊ 0⤋
Rewrite it as q(q-1)/q. Now cancel the q to get q-1.
2007-01-12 10:01:03 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
q^2-q
-----------
q
=q(q-1)/q=q-1
2007-01-12 09:59:57 · answer #5 · answered by Salih D 1 · 0⤊ 0⤋
factorizing this problem we get
q(q-1)
---------
q
therefore answer is q-1
2007-01-12 10:17:04 · answer #6 · answered by srinu710 4 · 0⤊ 0⤋