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given that the radius of the erath's orbit is 151000000 km?

2007-01-11 22:32:29 · 2 answers · asked by Mae 1 in Science & Mathematics Physics

2 answers

The orbit radius is nearer to 149 600 000 km

Orbit = 2 pi*r = 2 pi * 149 600 000
= 939 964 521.95 km

One orbit lasts one year.
One non-leap year = 31 556 926 seconds

Speed = distance/time
= 29.78 km/s

or 66 615.96 mph!

2007-01-11 22:43:05 · answer #1 · answered by bonshui 6 · 0 0

"Earth's average speed of revolution about the sun is 29.8 kilometers per second..

2007-01-12 06:37:37 · answer #2 · answered by Anonymous · 0 0

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