how many calories are required to heat 256g. of iron from 20 degrees C to 99 degreec C?

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would this be q=Hv or q=m*c*delta T?

2007-01-11 20:12:48 · 4 answers · asked by cc 2 in Science & Mathematics ➔ Chemistry

q = m c delta T

Because delta T = 99 C - 20 C, m = 256 g, and c = the heat capacity of iron.

2007-01-11 20:33:23 · answer #1 · answered by JoeSchmo5819 4 · 0⤊ 0⤋

The total energy equals Mass of iron * specific heat of iron * temperature rise = 256 g * 0.450 J/g K * (99-20) = 9101 J

2007-01-11 21:05:37 · answer #2 · answered by cordefr 7 · 0⤊ 0⤋

9101J = 2177 calories

2007-01-11 21:57:30 · answer #3 · answered by JJ 7 · 0⤊ 0⤋

Q = mc(t2 - t1)

2007-01-12 01:10:19 · answer #4 · answered by Anonymous · 0⤊ 0⤋