I have been trying this problem for the longest and it doesn't seem to be the right answer. It is a system of equation problem. PLZ HELP
m = n^2 - 3n
m = -2n^2 - 3n
2007-01-11 18:46:58 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
I suspect the ans to be zero 0. Equate both equations and you will get n^2 - 3n = -2n^2 - 3n.
Removing the -3n,you will get n^2 = -2 n^2.
Bringing everything to 1side,you will get either 3n^2 = 0 or -3n^2 = 0.Either way, the ans is still 0.
2007-01-12 02:59:05 · answer #1 · answered by Universal Studios 2 · 0⤊ 0⤋
Subtract the second equation from the first, to get
3n² = 0.
Thus n = 0 and m = 0.
2007-01-12 13:27:13 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
hey.. easy :D see where u have m = -2n^2 - 3n... well sub n^2 - 3n where u see M... so therefor; n^2 - 3n = -2n^2 - 3n,. then u can continue it from there :D hope it helps. GOOD LUCK :D
2007-01-12 02:56:10 · answer #3 · answered by NFLS121a 1 · 2⤊ 0⤋