A fisherman launches bait off a dock at a 25 degree angle.The bait reached a maximum hieght of 17m.
2007-01-11 18:38:50 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
1) We have the following formulas for the position and velocity.
x = v t cos p
y = v t sin p - (1/2) g t^2
v_x = v cos p
v_y = v sin p - g t
Here p is the angle, g is acceleration due to gravity, t is time, v is the initial speed.
2) At maximum height
y= v t sin p - (1/2) g t^2 = 17
v_y = v sin p - g t = 0
3) Solve for v and t.
t = (v/g) sin p and
v = sqrt (34 g/ sin^2 p) = sqrt (34 * 9.813 / sin^2 25deg) = 43.2 m/s
2007-01-11 22:00:54 · answer #1 · answered by cordefr 7 · 0⤊ 0⤋
About 43m/s assuming you mean 25 deg to the horizonatal. Highly improbable.
2007-01-12 05:52:51 · answer #2 · answered by JJ 7 · 0⤊ 0⤋
mach 3.1
2007-01-12 02:46:57 · answer #3 · answered by Z 5 · 0⤊ 1⤋