What is the angle of the hobby rocket?

Question

A hobby rocket is launched and reaches 75.5m in hieght an lands
143m from the launch point.

Answer 1

t = (vsinθ)/g
s = 2t(vcosθ)
s = 2v^2(cosθ)(sinθ)/g
v^2sin^2θ = 2gh
v^2 = (2gh/sin^2θ)
s = 2(2gh/sin^2θ)(cosθ)(sinθ)/g
s = (4h/sinθ)(cosθ)
s = 4h/tanθ
tanθ = 4h/s
tanθ = 4*75.5/143
tanθ = 2.1112
θ = 64.66°

Answer 2

My Guess is approximately 15 degrees ? But just a guess.

I transposed the numbers provided