A submarine is at -500 feet, or 500 feet below sea level. The ship is then directed to descend 650 feet, then to ascend 350 feet, then to descend 340 feet, then to ascend 150 feet, and then to descend to the ocean floor which is 1200 feet below sea level.
How many feet was the final descent?
2007-01-11 18:30:01 · 5 answers · asked by gurpreet 1 in Science & Mathematics ➔ Mathematics
-500 - 650 + 350 - 340 + 150 = - 990
The submarine is presently at 990 feet prior to final descent to 1200..
The question: How many feet was the final decent
1200- 990 = 210 feet
The final decent was 210 feet
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2007-01-12 01:53:16 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
Before the final descent to the ocean floor, the position of the submarine with respect to sea level (regarded zero) was: -500-650+350-340+150 = - 990 feet.
So the final descent was from 990 feet below the surface to 1200 feet below the surface , that is, 210 feet. Answer.
2007-01-13 11:56:03 · answer #2 · answered by Anonymous · 0⤊ 0⤋
-500 -650 +350 -340+150 - x = -1200
-990 -x = -1200
-x = -210
x = 210
The final descent was 210 Feet
2007-01-11 18:46:11 · answer #3 · answered by Brian F 4 · 0⤊ 0⤋
-500 - 650 + 350 - 340 + 150 = -990
-1200 - (-990) = -210
The final descent was 210 feet.
2007-01-11 18:34:29 · answer #4 · answered by Northstar 7 · 0⤊ 0⤋
It finally went 210 ft down to 1200 below sea level.
I did NOT copy the person who just answered.
2007-01-11 18:38:53 · answer #5 · answered by blah 3 · 0⤊ 0⤋