Can you explain why this factoring (ALGEBRA 2) problem change?

Question

Well IM reducing it and the book says it changes from x^2(X+3)-2(X+3)/(X+3)(X^2-3X+9) to (x^2-2)/(X+3)(X^2-3X+9). PLease help me It may not make sense but IM seriously stuck.

Answer 1

Here's a formula for ya: People + asking math questions on Yahoo Answers = Me starting to get pissed off.

Answer 2

Think of x+3 = Y :
x^2(X+3) -2 (X+3)/(X+3) (X^2-3X+9) = x^2-2/(X^2-3X+9)

To avoid "..." put spaces =), just discovered that myself

Answer 3

4(x-11)(x+11) x= 11 or -11 x^2 - 121 is a distinction of squares. The sq. root of 121 is 11, so that you would possibly want to destroy that down into (x-11) and (x+11). Then, you position each and each and every human being equation equivalent to 0 and be certain for x, Like this: x-11=0 x=11 x+11=0 x=-11

Answer 4

x^2(X+3)-2(X+3)/(X+3)(X^2-3X+9)... to (x^2-2)/(X+3)(X^2-3X+9).
Factor out (x+3) getting:
(x+3)[x^2-2)]/[(x+3)(x^2-3x+9)]
= (x^2-2)/(x^2-3x+9)
This is the correct answer.

Answer 5

x^2(X+3)-2(X+3) -> (x^2-2)(x+3)
---------------------- -----------------
(X+3)(X^2-3X+9) -> (x^3 +27) or (X+3)(X^2-3X+9)

Ok so i've simplified it down like that all you should have to do is cross out the (x+3)'s on top and bottom and your answer should be:

(x^2-2)
--------------
(X^2-3X+9)

Since you can't simplify it down anymore. I dunno why your book says you still have an (x+3) left.

Answer 6

There is some sort of typographic issue, probably parenthesization, because it doesn't work.

Answer 7

i think it will be best if you type the entire problem out

Answer 8

um... ur question is not clear.. pls type out clearly.. thnx...