Property one and two of Radical expressions?

Question

Use property one sqrt(ab) = sqrt(a) * sqrt (b)

to solve this problem with out using a calulator

sqrt50

and

sqrt72x^3

and finally

using property 2

sqrt(a/b) = sqrt(a) / sqrt(b)

to solve the following problem

sqrt 10/49

Answer 1

√50 =
√(25 * 2) =
√25 * √2 = 5√2

√(72x^3) = √(36 * 2 * x^2 * x)
=√36*√2*√(x^2)*√x
=6*√2*x*√x
=6x√2√x
=6x√(2x)

√(10/49)=√10/√49
=(√10)/7

I think the question wants you to leave the answer in as simple a root as possible. If neccassary you can calculate the approximate answer by plugging the numbers in a calculator.

Answer 2

sqrt50 = sqrt (25*2) = sqrt(25)*sqrt(2) = 5sqrt(2)

sqrt72x^3 = sqrt 36x^2*2x= sqrt(36x^2)*sqrt(2x) = 6x*sqrt(2x)

sqrt 10/49 = sqrt(10)/sqrt(49) = sqrt(10)/7

Answer 3

um.....its all approx, just get it down to numbers you kno

100^.5 = 25^.5*4^.4 = 5*2 = 10