Please help with this equation
Find the time required for an object to fall to the ground form a building that is 1400 ft high using the following formula
t=1/4sqrts in which s is the distance fallen.
2007-01-11 16:21:22 · 5 answers · asked by CookFrNW 3 in Science & Mathematics ➔ Mathematics
t = (1/4)* (1400 ft.)^(1/2)
t = approx. 9.354 seconds. according to the given equation.
2007-01-11 16:26:49 · answer #1 · answered by smawtadanyew 2 · 0⤊ 0⤋
t = 1/4sqroot(s), where s = 1400 ft.
Lets put the value of s in the given formula
=> t = 1/4 sqroot(1400)
=> t = 1/4 [10 * sqroot 14]
=> t = 1/4 [10 * 3.741]
=> t = 1/4 [ 37.41]
=> t = 9.3525 (approx.)
2007-01-11 17:01:37 · answer #2 · answered by rishi 2 · 0⤊ 0⤋
Using the given formula t=9.354Seconds. This is when s is kept in feet i.e. feet, pound second (fps) system. But if the formula
s=ut+asqr(t)/2 is applied and s is taken in meters as 427m and acceleration due to gravity as about 10m/sec2 then t = 9.241sec
2007-01-11 16:36:14 · answer #3 · answered by akhilesh v 2 · 0⤊ 0⤋
t = 0.25 x 1400**1/2 = 9.35 seconds
2007-01-11 16:28:02 · answer #4 · answered by Anonymous · 0⤊ 0⤋
t = s^.5 / 4
is...that what you meant?
well sub in
t = 1400^.5 /4
= 37.42 /4
= 9.4 sec
2007-01-11 16:28:35 · answer #5 · answered by Anonymous · 0⤊ 0⤋