How do you solve this problem?

Question

Na2SO4 (aq) + BaCl2 (aq) ===>BaSO4 (s) + 2NaCl (aq)

3.0 mol NaSO4 = --?--- g BaSO4
three moles of sodium sulfate equals how many grams of barium sulfate? Please show ur work i am really having trouble trying to figure out this problem.

Answer 1

unknown (1)
--------------------- x mol of known (3.0mol) = 3.0mol of BaSO4
known (1)

m=nxM
=3.0mol x 233.39 g/mol
m=700.17grams of BaSO4

Answer 2

Using the factor-label method:

Given x molar ratios of the two compounds in question from your balanced equation x the gram molar mass of the compound in question, as follows:

1 mol BaSO4 = 233 g BaSO4

3.0 mol Na2SO4 x 1 mol BaSO4/1 mol Na2SO4 x 233 g BaSO4/1 mol BaSO4 = 699 g BaSO4

(You get this answer by cancelling everything that appears both in the numerator and denominators of your problem and then multiplying all your numerators across and then your denominators across.)

If you need your answer to the proper number of significant digits, change your answer to scientific notation = 6.99 x 10^2 g BaSO4
round this to 2 significant digits (because this is the significance shown in the question), your correct answer is 7.0 x 10^2 g BaSO4.

P.S. Your molar ratios of 1 mol BaSO4/1 mol Na2SO4 are from the coefficients of your balanced equation.

Answer 3

The key is the conversion factor found in the equation (1 mol Na2SO4 = 1 mol BaSO4) and then the one you calculate for molar mass (x grams BaSO4 = y moles).

Answer 4

The equation appears balanced.

So, 3 moles of Na2SO4 yields 3 moles BaSO4

Look up the gram molecular weights of the elements in BaSO4, add them up, and multiply by 3, and you'll have it!