Homework question once again Algebra 2 First let me say if home work questions bother you than simply ignore?

Question

this question,seriously it just wastes yours & my time if u write this long paragraph about how I should do my own h.w.. I have done the last 27 problems & have a few left unfortunately I missed a day & the last couple of problems had to do w/ that,so w/ that being said this is a factoring assgn. It is in standard form,if you can explain how u got the answer it would be appreciated but I wont complain if you dont its 10:40 Im tired & just wanna finish my homework if I still need help I can ask the teacher in class but I do need to finish it tonight. so I will show u one I did so u know what form to put the answer in.
ex.3x^2+54+243 ( 3x + 22 ) ( x + 9 ) the numbers in the parenthesis is the answer,Im sure you know that : )
problems follow- 1.112a^2 - 168a+ 63 - I should know how to do this but the numbers are so large I've been trying for forever.
2.) x^2 + 19 + 88 =0 3.)8x^2 - 6x -5 =0
4.)9m^2 - 30 + 25 =0 5.) 40a^2+4a=0
6.)x^2+9x=- 20 7.) 5p2 -25 = 4p^2 +24

Answer 1

1.)112a^2 - 168a+ 63
= 16a^2-24a+9
= (4a-3)^2

2.) x^2 + 19x + 88 =0
(x+11)(x+8)=0 ---> x=-8 and x= -11

3.)8x^2 - 6x -5 =0
(4x-5)(2x+1) =0

4.)9m^2 - 30 + 25 =0
(3m-5)^2 = 0

5.) 40a^2+4a=0
4a(10a+1)=0

6.)x^2+9x=- 20
x^2+9x+20 =0
(x+5)(x+4) =0

7.) 5p2 -25 = 4p^2 +24
5p^2-4p^2= 24 +25
p^2=49
p= +/- 7

Answer 2

1.
112a^2 - 168a+ 63 =
(4a - 3)(28a - 21)

2.)
x^2 + 19 + 88 = 0
(x + 11)(x + 8) = 0

3.)
8x^2 - 6x -5 =0
(4x - 5)(2x + 1) = 0

4.)
9m^2 - 30 + 25 =0
(3m - 5)^2 = 0

5.)
40a^2 + 4a=0
4a(10a + 1) = 0

6.)
x^2 + 9x + 20 = 0
(x + 4)(x + 5) = 0

7.)
5p^2 - 25 = 4p^2 + 24
p^2 - 49 = 0
(p + 7)(p - 7) = 0

Answer 3

2) x^2+19+88 = (x+11)(x+8)
6) x^2+9x+20 = (x+4)(x+5)
3) 8x^2-6x-5 = (4x-5)(2x+1)
5) 40a^2+4a = 4a(10a+1)
7) 5p^2-25 = 4P^2+24
p^2-49= (p+7)(p-7)

I couldn't figure out number 4. Don't worry, math isn't an easy subject, but at least you'll be that much smarter in the end (lol).

Answer 4

[1]
112a^2 - 168a + 63
7(16a^2 - 24a + 9)
7(4a - 3)(4a - 3)
7(4a - 3)^2

[2]
x^2 + 19x + 88 = 0
(x + 11)(x + 8) = 0
x + 11 = 0
x = -11
x + 8 = 0
x = -8

[3]
8x^2 - 6x - 5 = 0
(4x - 5)(2x + 1) = 0
4x - 5 = 0
4x = 5
x = 5/4
2x + 1 = 0
2x = -1
x = -1/2

[4]
9m^2 - 30m + 25 = 0
(3m - 5)(3m - 5) = 0
(3m - 5)^2 = 0
3m - 5 = 0
3m = 5
m = 5/3

[5]
40a^2 + 4a = 0
4a (10a + 1) = 0
4a = 0
a = 0
10a + 1 = 0
10a = -1
a = -0.1

[6]
x^2 + 9x = -20
x^2 + 9x + 20 = 0
(x + 5)(x + 4) = 0
x = -5 or x = -4

[7]
5p^2 - 25 = 4p^2 + 24
5p^2 - 25 - 4p^2 - 24 = 0
p^2 - 49 = 0
p^2 = 49
p = 7 or p = -7

Answer 5

2) x^2 + 19 + 88

So look for 2 numbers that mult. to 88 and add 2 19 like....11 and 8

So 2) is (x+11)(x+8)

3) 8x^2 - 6x - 5 = 0
This one is slightly harder

So ill just use the quadratic equation

(-b +/- (b^2 - 4ac)^2) /2 From teh form ax^2+bx +c
6 +/- 36 - (4*8*-5) / 16 = 6 + 14 / 16 and 6- 14 / 16 = 20/16 and -8/16

Sorry lost interest....

Answer 6

First, you ought to element the trinomial. Mulitply -14 x 6 = -80 4 Now think of of two integers whilst greater provide you -80 4 and whilst added provide you -17. that must be -21 and four. Now chop up your center words into -21 and four. 6x^2 +4x -21x -14 Now element with tips from grouping the 1st 2 and the final 2 words. 2x(3x+2)-7(3x+2)=0 (2x-7)(3x+2) = 0 Now set each and each set of parentheses = to 0. 2x-7=0 2x=7 x=3.5 3x+2=0 3x=-2 x=-2/3

Answer 7

You should put clearer questions; anyway i think you forgot some " x "and a " ^ " in 7...
1°)
7(4x-3)^2
2°)
x = -sqrt(107) * i or sqrt(107) * i
3°)
8(x +1/2) (x-5/4)
4°)
x= sqrt(5) /3 or -sqrt(5) /3
5°)
x = 0 or -1/10
6°)
x = -5 or -4
7°)
x = 7 or -7

Answer 8

2.(x+8)(x+11)
3. (4x-5)(2x+1)
4.(3m-5)(3m-5)
ehh bored