A & B.
Remember: First, Outer, Inner, Last (FOIL)
First: 2x*x = 2^2
Outer: 2x*-2 = -4x
Inner: 3*x = 3x
Last: 3*-2 = -6
So: 2^2 - 4x + 3x - 6 = 2^2 - x - 6
First: 2x*x = 2^2
Outer: 2x*3 = 6x
Inner: -2*x = -2x
Last: -2*3 = -6
So: 2^2 + 6x - 2x - 6 = 2^2 + 4x - 6
.
2007-01-11 15:52:43
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answer #1
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answered by Johhny Drama 5
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A. is the incorrect answer.
The RHS of the equation = 2x^2 -x-6 which is certainly not equal to 2x^2-6
2007-01-11 23:55:38
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answer #2
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answered by ironduke8159 7
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A and B are not true., because
A is
2x^2 - 6
=2(x^2 - 3)
=2(x + sqroot3)(x - sqroot3)
and, B is
2x^2 + x - 6
= 2x^2 + 4x - 3x - 6
= 2x(x + 2) - 3(x + 2)
= (x + 2)(2x - 3)
Hence, both A and B are incorrect.
2007-01-12 00:06:05
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answer #3
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answered by rishi 2
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A and B.
A. (2x+ 3)(x - 2) = 2x^2 - 4x + 3x - 6 = 2x^2 - x -6
B. (2x - 2) (x + 3)= 2x^2 +6x - 2x - 6 = 2x^2 +4x -6
2007-01-11 23:53:31
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answer #4
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answered by Jerry P 6
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A RHS = 2x^2 -4x + 3x - 6
B RHS = 2x^2 + 6x - 2x - 6
c RHS = 2x^2 - 11x + x -6
d RHS = 2x^2 + 11x - x - 6
SO......A and B
2007-01-11 23:57:16
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answer #5
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answered by Anonymous
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a is false because if you foil the right side there would be a -x term
b is false because the coefficent of x should be 4, not 1
c is true
d is true
2007-01-11 23:54:27
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answer #6
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answered by Anonymous
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A.
B.
Verify by using FOIL method.
2007-01-11 23:57:20
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answer #7
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answered by S. B. 6
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2007-01-12 11:25:53
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answer #8
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answered by Anonymous
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