The motor of an elevator develops power at a rate of 2500W. At what speed can a 1200kg load be raised?

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The motor of an elevator develops power at a rate of 2500W. At what speed can a 1200kg load be raised?

Please explain step by step.

2007-01-11 15:31:55 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics

2 answers

P = Fv
=> 2500 = (mg) v
=> v = 2500 / (1200 . 9.8) [I'm using g = 9.8 m/s^2 here; if you've been told to use a different value, substitute that into this calculation]
=> v = 0.21 m/s.

2007-01-11 15:35:55 · answer #1 · answered by Scarlet Manuka 7 · 1⤊ 0⤋

3.6 miles an hour

2007-01-11 23:35:21 · answer #2 · answered by Anonymous · 0⤊ 1⤋