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The equation for the decomposition of silver oxide is 2Ag2O---4Ag + O2. Set up a proportion to calculate the number of silver atoms produced and the number of oxygen molecules released when one g of silver oxide is broken down. There are 2.6 x 10 to the 21st power molecules in one g of silver oxide. Help me I'm so stuck................

2007-01-11 15:20:53 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

In the initial gram of Ag2O, we are told that 2.6E21 molecules are present. Each of these contains 2 atoms of silver, so silver atoms total 5.2E21. Each of these produces half a molecule of oxygen, so oxygen molecules total 1.3E21.

2007-01-11 15:45:21 · answer #1 · answered by Anonymous · 0 0

For every two moles of Ag2O, the reaction produces 4 moles Ag and 1 mol oxygen gas.

Those are your ratios....hope it helps.

2007-01-11 15:50:27 · answer #2 · answered by teachbio 5 · 0 0

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