how do i get x-3y=-18 into the form of y=?

Question

how can i write it in slope intercept form?

Answer 1

isolate the y

-3y=-18-x
y=-18/-3 -x/-3
y=6+x/3

Answer 2

Starting with

x-3y = -18

Subtract x from both sides:

-3y = -18 - x

Now, divide both sides from -3:

y = (-18/-3) - (x/-3)

Simplifying, that becomes:

y = 6 + (1/3)*x

Slope is 1/3 and intercept is 6.

Answer 3

the x would be the horizontal axis. The y will be the vertical axis.
here are the steps...
1. x - 3y = -18
2. -3y = -18 - x
3. 3y = -1 (-18 -x)
4. 3y = 18 + x ----> 3y = x + 18
5. y = (18 + x) / 3 which is the final answer

Answer 4

x-3y=-18 into the form of y=?

you have to get y by itself

subtract x from both sides: -3y = -18 - x
divide by -3: y = (-18-x)/-3

now you can split the fraction up into two frations:
y = -18/-3 - x/-3

see they have the same denominator and the same sign inbetween them.

now simplify: y = 6 + x/3

Answer 5

1) move variables around until you have only y's on the left

-3y = -x -18

2) divide both sides by the factor of y (in this case, -3)

(-3/-3)y = (-1/-3) + (-18/-3)

y = (1/3)x + 6

Answer 6

You divide 3y and 18 by 3..
so then your equation is:
x-y=-6
your y intercept is 6
thats weird... Im doing the exact same thing in math right now!! I'm ini 7th grade!

Answer 7

x-3y=-18 subtract x from each side
-3y=-x-18 divide both sides by -3
y=x/3+6

Answer 8

x-3y=-18
-3y= -(18+x)
y= -(18+x)/-3
y=6+x/3

Answer 9

y = ( 18 - x ) / 3

Answer 10

x-3y=-18

-3y=-18-x

-3y/-3=(-18-x)/-3

y=6+x/3