square root of 2x+3 - square root of x+1=1
so far i have this:
square root of 2x+3=1+square root of x+1
so i squared both sides and got this:
2x+3=x2+2x+2
idk what to do from here. i keep getting the wrong answer!!! please help!!!
2007-01-11 14:51:30 · 3 answers · asked by sweet_tangerine 4 in Education & Reference ➔ Homework Help
how'd you get 3??? thats right, i just dont know how to get there.
2007-01-11 15:03:32 · update #1
x = 3 and -1. Try them both and they work!
You didn't square both sides properly. You have to use the formula a2 + 2ab + b2.
Here's the work:
2x+3 = 1 + 2sqrt(x+1) + (x+1)
2x+3 = 2 + 2sqrt(x+1) + x
2x = -1 + 2sqrt(x+1) + x
x = -1 + 2sqrt(x+1)
1 + x = 2sqrt(x+1) then square both sides
x2 + 2x + 1 = 4x + 4
x2 - 2x - 3 = 0
(x - 3)(x + 1) = 0
x = 3 and -1
2007-01-11 15:01:38 · answer #1 · answered by Amber 2 · 1⤊ 0⤋
From what I can tell, if you square the total equation you should get:
2x+3+x+1=1
3x+4=1
3x=-3
x=-1
2007-01-11 22:58:25 · answer #2 · answered by gpwarren98 3 · 0⤊ 0⤋
too confusing
dont bother here just ask teacher or some nerd in class
2007-01-11 22:58:42 · answer #3 · answered by Anonymous · 0⤊ 1⤋