(8X-2X^2+7X^3)-(X^3-2X^2+3X)
(5X-6X^3) does it matter what order it is in? Also is that the final answer and right?
2007-01-11 14:35:51 · 4 answers · asked by theoneandonly4251 2 in Science & Mathematics ➔ Mathematics
nope, its 5x+6x^3 , and u can simplify it and make it x(5+6x^2). order doesnt matter, unless your teacher wants a certain way, ie. accending or decending order.
2007-01-11 14:40:00 · answer #1 · answered by agenthounddog 2 · 0⤊ 0⤋
(8X-2X^2+7X^3)-(X^3-2X^2+3X) =
8x - 2x^2 + 7x^3 - x^3 + 2x^2 - 3x =
agruping all the terms with the same power..
5x + 6x^3
Furthermore.. if you want...
5x + 6x^3 = x(5 + x^2)
OK?!?!?
2007-01-11 14:42:48 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(8x-2x^2 + 7x^3) -(x^3-2x^2+3x)
distribute and you have...
(8x-2x^2 + 7x^3) -x^3+2x^2-3x=
(8x-3x)+ (-2x^2 + 2x^2) + (7x^3-x^3)
then...
(5x) + (6x^3)
so 5x + 6x^3 is the answer
2007-01-11 14:44:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The correct answer is 5X + 6X^3.
It doesnt matter what the order is.
2007-01-11 14:40:04 · answer #4 · answered by sg 2 · 0⤊ 0⤋