Im doing my algebra hw, and im in 7th grade, and im stuck with a question...?

Question

the question is (we're learning slope) Find the slope of the kube through A(4, -3) abd B(1, -5) using A fore (x2, y2) and B for (x1, y1).
Im not looking for answers; im looking for help on how to slove this(ps i nned to go to bed so please hurry)

Answer 1

to points (x2,y2) = (4,-3) = A and (x1,y1) = (1,-5) = B make a line not a cube.. but.. all you do to calculate the slopw if to find the rise/run or (change in y)/(change in x)...

so... (y2-y1)/(x2-x1) gives your slope.. just substitute in the numbers from the coordinates given for your points and reduce the fraction...

so you get: (-3 - (-5)) = (y2 - y1) = (-3 + 5) = 2 for change in y
and: (4-1) = (x2-x1) = 3 for change in x...

or: 2/3 for rise/run or slope...

by the way, if you calculate this slope using B for (x2,y2) and A for (x1,y1) you will get the EXACT SAME SLOPE calculation.. why? because it does not matter which two points on the line you select and in what order, the line always has the same slope or else it would not be a straight line.

Answer 2

the formula is (y1 - y2) / (x1 - x2). So set up that would be (-5 - -3) / (1 - 4). That brings you to -2/-3 which equals 2/3

Answer 3

to respond to those, you want to isolate the "x" or "y" (the unknown) onto one aspect of the equation. a million) y + 4/3 = -a million (subtract 4/3 from both aspect) y + 4/3 -4/3 = -a million -4/3 (4/3 -4/3 =0) -a million - 4/3 is an same as -a million + -4/3 y = -a million - 4/3 y = -7/3 2) -(x-5) is an same as -x +5 -x + 5 = -thirteen.5 (subtract 5 from both aspect) -x = -18.5 x = 18.5

Answer 4

slope = (y2-y1)/(x2-x1)=(-5-3)/(1-4)

Answer 5

-5--3/1-4
slope: -2/-3