L has y-intercept (0, 2) and is perpendicular to the line with equation:2x – 3y = 6.?

Question

Determine whether the side through the points (2, 3) and (11, 6) is perpendicular to the side through the points (2, 3) and (-3, 18).

Answer 1

I have no idea which part you are trying to answer... you have a line L (I guess) and it is perpendicular to the line with equation: 2x -3y = 6...

ok, first you change that equation to the slope intercept form:
y = mx + b; where m is the slope and b is the y-intercept (or the y value when x = 0)...

then, line L must have a slope which is the negative-inverse of the given equation's slope.. but from there I'm not sure what you want to find out...

Then you give coordinates for 4 points and say that they are sides.. sides to what?.. you can get the equation of the lines by calculating the slope (rise/run) and then if the two slopes are negative-inverse of each other the lines are perpendicular.

Answer 2

Find the slopes of the two "sides" (I'll assume they are lines). When two lines are perpendicular, their slopes are NEGATIVE RECIPROCALS. That means, for example, if one has a slope of 3, the perpendicular to it has a slope of -1/3.

Let's find these slopes with (difference in y's) divided by (difference in x's).

The first "side" has a slope of 3/9 whis is just 1/3. The second has a slope of 15/-5 which is -3.

So they are indeed perpendicular.