Can someone show the steps and where I would graph this on the # line. Do I minus 2 from both sides? and dived 3 by both sides?
2007-01-11 14:01:21 · 5 answers · asked by theoneandonly4251 2 in Science & Mathematics ➔ Mathematics
Two different equations
11<3X+2
11-2<3X+2-2
9<3x
9/3<3x/3
3
3X+2<20
3X+2-2<20 -2
3X<18
3X/3<18/3
X<6
3
3
2007-01-11 14:16:35 · answer #1 · answered by Hawaiian Nut 3 · 0⤊ 0⤋
11 < 3x+2 <20
--> 11-2 < 3X < 20-2
--> 9 < 3X < 18
--> 9/3 < X < 18/3
--> 3 < X < 6
This means theres only 2 things that X can be to satisfy the equation:
X = 4 ....... in which case 3X+2 = 14
or X = 5 ....... in which case 3X+2 = 17
2007-01-11 22:07:00 · answer #2 · answered by Yahya d 3 · 0⤊ 0⤋
your inequality is 11<3x+2<20, solving you will get
11-2<3x<20-2
=> 9<3x<18
=>9/3
so simply draw the open inequality (3,6) on the number line
2007-01-11 22:08:33 · answer #3 · answered by bonzion 1 · 1⤊ 0⤋
No, you "subtract" 2 from each expression and then divide each expression by 3.
2007-01-11 22:08:25 · answer #4 · answered by crane 1 · 0⤊ 0⤋
yes, youre right, just use order of operations.
2007-01-11 22:06:25 · answer #5 · answered by ally 2 · 0⤊ 0⤋