Y^-2Z^-4
_________
Y^3Z^-2
the ^ means its an exponent help please!!!
2007-01-11 13:53:44 · 7 answers · asked by love2figureskate 4 in Science & Mathematics ➔ Mathematics
can you please tell me how to do it also because i have to show my work and I need to understand it
2007-01-11 13:57:34 · update #1
and it has to be simplified so there is now exponents in the denominator
2007-01-11 13:58:00 · update #2
Answer: y^(-2z)
since y^(2z)^-4 = y^(-8z) and y^(3z)^-2 = y^(-6z)
y^(-8z) / y^(-6z) = y^(-8z - (-6z)) = y^(-2z)
2007-01-11 13:59:15 · answer #1 · answered by crane 1 · 0⤊ 0⤋
to solve this you will have to rewrite using positive exponent. to change the neg to pos exponent you assume that the neg exponent is over 1,then you plip over the 1.the pos exponent is already 1 over the number.
y^-2z^-4
____________ this becomes.
y^3z^-2
1/y^3 * 1/y^2 * 1/z^-2 * z^4 add like terms exponent.
1 / y^3+2 * 1 / z^4-2
1 /y^5 * z^2
the answer = 1/y^5z^2
i hope you are able to understand this.cheers.
2007-01-11 14:43:58 · answer #2 · answered by bright 247 2 · 0⤊ 0⤋
think of it as y*y*z*z*z*z
___________
y*y*y*z*z and you can eliminate 1 y or z if there is a "match" on the other side of the dividing line, so you can eliminate 2 y's from top and bottom, and 2 z's as well. This leaves you with 2z's on top and 1 y on the bottom: Z^2/Y remains
2007-01-11 14:06:46 · answer #3 · answered by lynn y 3 · 0⤊ 0⤋
1/(Y^5*z^2)
2007-01-11 13:56:59 · answer #4 · answered by bozo 4 · 0⤊ 0⤋
Y^-1z^2 or z^2/y^1
2007-01-11 13:58:18 · answer #5 · answered by stewart m 2 · 0⤊ 0⤋
when dividing, you subtract the exponents
Y^-2Z^-4
_________
Y^3Z^-2
-2-3=-5
-4-(-2)=-2
so it becomes: (Y^-5)(Z^-2)
2007-01-11 13:58:02 · answer #6 · answered by borscht 6 · 0⤊ 0⤋
YZ^2
2007-01-11 13:57:30 · answer #7 · answered by Anonymous · 0⤊ 0⤋