A bicycle wheel is resting against a small step whose height is h=0.120 m. The weight and radius of the wheel are W=25.0 N and r=0.340 m. A horizontal force F is applied to the axle of the wheel. As the magnitude of F increases, there comes a time when the wheel begins to leave the ground. What is the magnitude of the force when this happens?
2007-01-11 13:52:40 · 2 answers · asked by Someone 1 in Science & Mathematics ➔ Physics
Wheel touches edge of step. Draw a picture. Twist due to force turning wheel one way just equals twist due to weight of wheel. So
F (.34 - .12) = W (sqrt(.34^2 - .22^2) or F = 29.5 N
2007-01-11 15:03:17 · answer #1 · answered by hello 6 · 0⤊ 0⤋
Please stop asking us to do your homework for you. Just try, and then tell your teacher you tried but couldn't figure it out.
2007-01-11 21:57:22 · answer #2 · answered by flyingbirdyaws 2 · 1⤊ 0⤋