F=1/(square root 2pie(R1R2C1C2)) solve for C1?

Answer 1

Step 1: Set both sides of the equation to the negative first power.
(Take the reciprocal of both sides)

At this step you should have the following:

(1/F) = square root(2*pi * (R1R2C1C2).

Step 2: Now you need to get rid of the square root on the
right side of the equation. To do this square both sides.

(1/F)^2 = 2pi*(R1R2C1C2).

Step 3: Divide both sides of the equation by (2* pi *(R1R2C2))

Your Final answer should be

C1= ((1/F)^2)/(2*pi*(R1R2C2).

Hope this helps.

Answer 2

That might do better in the math section. Physicists only do computation, not so much randomly generated algebra.