How much of a 75% copper alloy should be melted into 62kg of a 35% copper alloy to produce an alloy which is 50% copper?
2007-01-11 13:26:34 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Based on your question, I believe that you would use a weighted average where some weight of the 75% alloy and 62kg of the 35% alloy are combined to get a 50% alloy. So:
(0.75x + 0.35(62))/(x + 62) = 0.5
0.75x + 21.7 = 0.5x + 31
0.25x = 9.3
x = 37.2kg of the 75% alloy
to check
(0.75(37.2) + 0.35(62))/(37.2 + 62) = 0.5
0.5 = 0.5
2007-01-11 13:43:10 · answer #1 · answered by Patrick 5 · 0⤊ 0⤋
Ok you have two variables:
x = copper alloy
y = unknown alloy (final alloy)
Therefore, you need two equations:
0.75x + 62 = 0.5y
62 = 0.35x
x = 177.14 kg
y = 389.71 kg
You get it?
2007-01-11 21:35:58 · answer #2 · answered by casher19 1 · 0⤊ 0⤋
20%
2007-01-11 21:29:33 · answer #3 · answered by slickbabe_model_03 2 · 1⤊ 0⤋
Open your mathbook to this sction and see examples and you actually READ them â¥
2007-01-11 21:29:53 · answer #4 · answered by ♥Choco Lover♥ 3 · 0⤊ 0⤋
????!!!!!! UMMMMM- hmmmmmm- is this really a question??
2007-01-11 21:30:07 · answer #5 · answered by skygirlchristine 2 · 0⤊ 0⤋