2007-01-11 12:44:56 · 9 answers · asked by teddybears 3 in Science & Mathematics ➔ Physics
The firing pin strikes the primer iginting the powder thus driving the bullet out of the weapon
2007-01-11 12:54:14 · answer #1 · answered by It's been awhile 6 · 1⤊ 0⤋
The brain sends a signal to the finger which squeezes the trigger that releases the spring that pushes the hammer onto the firing pin which impacts the cartridge shell which detonates the primer which ignites the powder which explodes, forcing the bullet out the barrel of the gun.
Ummm...what was your question again?
2007-01-11 21:01:01 · answer #2 · answered by Mez 6 · 0⤊ 0⤋
The "bullet" is just the tip of the loaded cartridge - the part that zooms out the barrel. The part of the firearm that hits the primer, though, is either the firing pin or the striker, depending on the type of firearm.
2007-01-13 16:03:28 · answer #3 · answered by Manevitch 4 · 0⤊ 0⤋
Nothing "strikes the bullet". The firing pin strikes the primer, located in the base of the cartridge, causing the big boom that makes the bullet go.
2007-01-11 20:53:12 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Actually, what you're thinking of is the
Firing Pin
The hammer strikes the firing pin, not the bullet, unless there is a hammer/firing pin combo type hammer.
2007-01-11 20:52:28 · answer #5 · answered by Living In Korea 7 · 0⤊ 2⤋
The hammer.
2007-01-11 20:52:41 · answer #6 · answered by mailatac 3 · 0⤊ 2⤋
The hammer.
2007-01-11 20:48:19 · answer #7 · answered by bubu 4 · 0⤊ 2⤋
Dont listen to bubu, its a hammer
2007-01-11 20:48:41 · answer #8 · answered by pop c 2 · 0⤊ 2⤋
The piston.
2007-01-11 21:35:21 · answer #9 · answered by flyingbirdyaws 2 · 0⤊ 1⤋