Pythagorean theorem?

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How would you solve 5 squared + x squared = x + 1 squared ?

2007-01-11 12:06:19 · 4 answers · asked by Kate! 3 in Science & Mathematics ➔ Mathematics

5^2+x^2=(x+1)^2
25+x^2=x^2+2x+1

x^2-x^2-2x+25-1=0
-2x+24=0
-2x=-24
2x=24
x=12

2007-01-11 12:15:50 · answer #1 · answered by Antonio R 3 · 0⤊ 0⤋

25 + x^2 = (x+1)^2
25 + x^2 = x^2 + 2x + 1

24 = 2x

x =12

The sides of your triangle are 5, 12, and 13. (A common Pythagorean triple, memorize it)

2007-01-11 20:10:36 · answer #2 · answered by mlw1235 2 · 0⤊ 0⤋

Here is my clear solution
25 + x squared = x squared +2x+1
25 = 2x + 1
24 = 2x
12 = x

2007-01-11 20:12:37 · answer #3 · answered by Anis Z 1 · 0⤊ 0⤋

multiply out (x+1)^2

5^2 + x^2 = x^2 + 2x + 1
25 = 2x +1
x=12

2007-01-11 20:11:04 · answer #4 · answered by Modus Operandi 6 · 0⤊ 0⤋