If a plane has to dump fuel, from a height of 125m...?

Question

If a plane has to dump fuel, from a height of 125m, before landing to avoid a firey crash, How long would it take to for the fuel to fall to the ground?
Im stuck at :
125=0(t) + [(9.8)(t)^2 (1/2)]

I know that I can take out the 0t because it will equal zero not matter what t is. Im having a slight problem with the algebra.

Answer 1

Taking your equation on the assumption that the plane is flying horizontally

125 = 0(t) + [(9.8)(t)^2 (1/2)]
125 = 4.9 t^2
Dividing both sides by 4.9
125/4.9 = t^2
Taking square root of both sides
5.05 = t

t = 5.05 seconds

Answer 2

125 = 1/2 * 9.8 * t^2
multiply the 1/2 and the 9.8 to get
125 = 4.9 * t^2
divide both sides by 4.9 to get
125 / 4.9 = t^2
or
25.5 = t^2
take the square root of both sides to get
SQRT(25.5) = t
or
5 = t
(rounded to the nearest whole)