If a plane has to dump fuel, from a height of 125m...?

Question

If a plane has to dump fuel, from a height of 125m, before landing to avoid a firey crash, How long would it take to for the fuel to fall to the ground?
Im stuck at :
125=0 (delta t) + [(9.8)(delta t) / 2]

Answer 1

I dunno. You're only going to get an approximation anyway 'cause you haven't given the plane's rate of descent. Let's just assume the plane's not descending. LOL.
I think it's like x = (1/2) a * t ^ 2
like, 125m = 1/2 (9.8 m/sec^2) t^2
like, hm, 250 sec^2 = 9.8 t^2
like, 25.51 sec^2 = t ^ 2
Now you need to take the square root of both sides and you get
t = 5.05 seconds

So there's your answer. 5.05 seconds.

Now here's a question for you:
How long before the fire department reaches the trailer park all that fuel landed on?

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I see you've asked this question twice. I looked at the others' answers. I think mine is better. I carried the units through (you know, meters, and seconds). Always carry your units through your calculations. Fewer errors that way. Good luck.

Answer 2

Assuming the plane is in level flight (which it probably won't be) when it dumps,
s = (1/2)at^2
t = √(2s/a)
t = √(2*125/9.8)
t = 5.05 s