2007-01-11 10:48:26 · 5 answers · asked by Turnip 3 in Science & Mathematics ➔ Chemistry
Concentration of H+ = inverse log of -pH.
10^-3.08 = 8.3x10^-4M.
2007-01-11 10:59:40 · answer #1 · answered by Picalo911 3 · 1⤊ 0⤋
The two answers so far are half-correct. pH is related to the activity of the hyrogen ion rather than the concentration so pH3.08 will be equal to a hydrogen ion activity (or effective concentration) of 8.3x10^-4 moldm^-3. To obtain the concentration you will need to divide by the activity coefficient for H+ at this activity/concentration. The solution is sufficiently dilute that it might be reasonable to assume an activity coefficient of 1.0 so your concentration is also 8.3x10^-4 moldm^-3, but it will actually be somewhat less than 1.0 so the concentration will be somewhat more than 8.3x10^-4 moldm^-3.
2007-01-14 06:09:33 · answer #2 · answered by beernutuk 3 · 0⤊ 0⤋
on account that pH = -log [H+], [H+] = 10^-pH once you do this calculation, the fee you get is already in mol/L So, if pH = 2.40 2, [H+] = 10^-2.40 2 = 3.8 X 10^-3 mol/L if pH = 11.21, [H+] = 10^-11.21 = 6.2 X 10^-12 mol/L
2016-11-23 12:48:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
you do 10^-3.08
so it is .0008317637711 or 8.317*10^-4
2007-01-11 11:03:07 · answer #4 · answered by fregosteg 2 · 1⤊ 0⤋
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2007-01-11 10:51:12 · answer #5 · answered by all_roads_lead_home 2 · 1⤊ 2⤋