How many grams of Carbon Dioxide produce when 23.5 grams of 1-heptanol react with excess oxygen in combustion?

Question

In a combustion reaction, I mean. This is the equation

2 C7H16O (l) + 21 O2 (g) → 14 CO2 (g) + 16 H2O (g)

Answer 1

is the answer 65.1 g of CO2
steps:

you need to convert the grams of heptanol into moles first

23. 5 g of heptanol 1mol of heptanol =0.2022793 mol of hep
116.176 g of heptanol


Then you do the molar jump from heptanol to carbon dioxide

0.2022793 mol of hep 14 mol of C02 =1.415955103 mol C02
2 mol of heptanol

Then convert it again from moles to grams'

1.415955103 mol C02 46.009 g of C02 = 65.1
1 mol of CO2