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A 18.7 kg block is dragged over a rough, hor-
izontal surface by a constant force of 130 N
acting at an angle of 29 above the horizon-
tal. The block is displaced 33.3 m, and the
coefficient of kinetic friction is 0.187.
The acceleration of gravity is 9.8 m/s2 :
Find the work done by the 130 N force.
Answer in units of J.

part2
Find the work done by the force of friction.
Answer in units of J.

part 3
If the block was originally at rest, determine
its final speed. Answer in units of m/s.

2007-01-11 09:40:06 · 1 answers · asked by kavita 1 in Science & Mathematics Physics

1 answers

1)
W = (130)(33.3)cos29 J

2)
W = (33.3)(0.187)(18.7*9.8 - 130sin29) J

3)
v = √(2(W1 - W2)/18.7) m/s

2007-01-11 09:59:18 · answer #1 · answered by Helmut 7 · 0 0

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