is sin(-pi/3)=sin(pi/3) true or false? and why?

Answer 1

It is false; if it were true, then that would imply sine is an even function. But it's not; sine is an odd function.

Also, sin(-pi/3) can also be written as sin (-pi/3 + 2pi), since you obtain the same point on the unit circle by going one revolution. sin(-pi/3 + 2pi) = sin(-pi/3 + 6pi/3) = sin(5pi/3)

sin(5pi/3) = -sqrt(3)/2, and
sin(pi/3) = sqrt(3)/2

As you can see, they're not equal.

Answer 2

It's false: sin(-pi/3) = -sin(pi/3).
Expand sin(0 - pi/3) = sin 0 cos pi/3 - cos 0 sin pi/3.
Now sin 0 = 0 and cos 0 =1 and so you get -sin(pi/3).

Answer 3

no it's false, the sine fuction is Odd, not even, hence Sin(- anything) = - Sin(anything)....therefore, sin(-pi/3) = - sin(pi/3)

Answer 4

In general sin(-x) = -sin(x)
So the statement is false.

Answer 5

sin(pi/3) is equal to sqrroot(3)/2
sin( -pi/3) is equal to negative sqrroot(3)/2

so the answer is false

hope this helps

Answer 6

False
sin(-π/3)=-√3 /2
sin (π/3)=√3 /2
sin is an odd function.

Answer 7

false, because you need to do your own homework!