Find exactly: sin 30˚cos45˚
2007-01-11 09:02:25 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
.5 and squareroot of 2 over 2.
2007-01-11 09:06:52 · answer #1 · answered by phantomreincarnated 1 · 0⤊ 0⤋
sin 30˚=1/2
cos45˚=√2 /2
sin 30˚cos45˚=(1/2)(√2/2)=√2 /4
2007-01-11 09:25:07 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
cos 45 = 1 and the sin 30 = 0.5
2007-01-11 09:17:22 · answer #3 · answered by 1ofSelby's 6 · 0⤊ 0⤋
sin 30 exactly = .5
cos 45 exactly = .5*sqrt(2)
Therefore sin 30˚cos45˚ exactly = .25*sqrt(2)
2007-01-11 09:09:51 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
sin(30)cos(45)
The good news is that 30 degrees and 45 degrees are known values on our unit circle. In radians, they are pi/6 and pi/4 respectively.
sin(pi/6) cos(pi/4)
(1/2) (sqrt(2)/2) = sqrt(2)/4
2007-01-11 09:10:38 · answer #5 · answered by Puggy 7 · 0⤊ 0⤋
sin30 = 1/2
cos45 = sqrt2 / 2
So 0.5 x sqrt2 / 2 = sqrt2 / 4
2007-01-11 09:07:21 · answer #6 · answered by salv MQ 2 · 0⤊ 0⤋
i dont take troometric
im only in algeabra1
i will probly be learning it when im a senior
( im in 8th grade im takin 9th grade math )
2007-01-11 09:08:27 · answer #7 · answered by sarah w 2 · 0⤊ 0⤋