A rectangle is 4 times as long as it is wide. A second rectangle is 5cm. longer and 2 cm. wider than the first. The area of the second rectangel is 270 square cm. greater than the first. What are the dimension of the original rectangle?
2007-01-11 08:45:56 · 3 answers · asked by gloriousnina 2 in Science & Mathematics ➔ Mathematics
Width = 20
Length = 80
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Let's walk through the solution
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First rectangle
Width = x
Length = 4x
Second rectangle
Width = x+2
Length = 4x + 5
Area1 = (x)(4x) = 4x^2
Area2 = (x+2)(4x+5) = 4x^2+13x+10
We know Area2 = 270 + Area1
So...
4x^2+13x+10 = 4x^2 + 270
Simplying...
13x = 260
Solving for x = 20 (width of first rectangle)... so the length is just 4*20 = 80.
2007-01-11 09:04:55 · answer #1 · answered by Charlie 2 · 1⤊ 0⤋
2
2007-01-11 16:52:55 · answer #2 · answered by 9 of 9 3 · 0⤊ 1⤋
width = 20
length = 80
2007-01-11 16:55:26 · answer #3 · answered by Ray 5 · 1⤊ 1⤋