MATH QUESTION!!! please help?

1 ⤊

MATH QUESTION!!! please help?

Evaluate 10^log-a+log(base 3)3^-a. give an exact answer. no calc. please show work.

2007-01-11 06:45:09 · 2 answers · asked by Anna 2 in Science & Mathematics ➔ Mathematics

2 answers

10^log(-a)+log(base 3)3^(-a)

The The first log is assumed to be log 10 so it cancels with the 10 as the base of the exponential function. The log(base 3) cancels the base of the exponent 3. So you have -a+(-a)=-2a

2007-01-11 06:52:54 · answer #1 · answered by Professor Maddie 4 · 1⤊ 0⤋

Evaluate 10^log-a+log(base 3)3^-a.
-a+(-a) = -2a

This is because log (base x) x^n = n, and 10 ^log x = x

2007-01-11 14:57:20 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋