Multiplying Fractions. 3 problems. THANKS~?

Question

1. what is -17 1/2 convereted into
a.-35/4
b.35/4
c.-35/2
d.35/2

2. a^2-7a + 6 / 2a^3 - 3a^2 multipied by 4a^3 -9a/ a^2-10a+24

3.4a^2 -b^2 / 4c^2 -d^2 multipied by (2c-d/2a+b)^2

Thanks So mucho!!!

Answer 1

1. A b/c = (Ac+b)/c
-[17*2 + 1]/2
-35/2

2. I recommend factoring everything, and multiply the numerators together and divide that by the product of the denominators.:

[ (a-6)(a-1) * a(2a-3)(2a+3) ]÷ [ a²(2a-3) * (a-6)(a-4) ]

Now we can divide out like terms:

(a-1)(2a+3) ÷ a(a-4)
And you can do more with it if you want. I'd leave it like that, personally.

3. (2a+b)(2a-b) * (2c-d)² ÷ (2c+d)(2c-d) * (2a+b)²

(2a-b)(2c-d) / (2a+b)(2c+d)

Answer 2

1. what is -17 1/2 convereted into
a.-35/4
b.35/4
c.-35/2
d.35/2
Take denominator times whole number and add numerator and put sum over denominator. So (2*17+1)/2= -35/2 because there was a minus sign in the problem. So answer is c.

2. a^2-7a + 6 / 2a^3 - 3a^2 multipied by 4a^3 -9a/ a^2-10a+24
= [(a-1)(a-6)]/[a^2(2a-3)]* [a(2a-3)(2a+3)]/[(a-6)(a-4)]
= (a-1)(2a+3)/a(a-4)

3.4a^2 -b^2 / 4c^2 -d^2 multipied by (2c-d/2a+b)^2
= (2a-b)(2a+b)/(2c-d)(2c+d) * (2c-d)^2/(2a+b)^2
= (2a-b)(2c-d)/2c+d)(2a+b)

Answer 3

1. -17 1/2 = -35/2

Answer 4

- (17*2+1) / 2
-35/2