From these experiments I have found out that as I added a bulb to the circuit the voltage increased.?

Question

this is because.....?

Answer 1

If you did this with a battery or transformer rather than the mains - which apparently has an infinitely low resistance - the following is the reason.
Using a battery/transformer as the voltage source produces a certain voltage when there is no connection between its terminals.
When a resistance is connected across the terminals currents flows. The voltage across the terminals falls because part of the voltage the source can produce in open circuit is use to get current to flow INSIDE that source.
The higher the internal resistance of the source the less current will flow. A 'dry cell' like a torch battery has a high internal resistance - about 1 Ohm whereas a car battery - lead acid - has a low internal resistance about 1/50th Ohm. the current which can be provided by a dry cell is therefore very limited whereas lead/acid can produce very high currents eg to start a car.
Enough waffle let's have a simplifsimplifiedd example.
A cell/transformer can produce 2 volts and has an internal resistance of 1 Ohm. If a 1 Ohm resistance is connected across its terminals a current of 1 Amp will flow (2/1+1 =1) through it. The voltage across the terminals will fall to 1 Volt as the 'other' volt is driving the current through the source.
If a 3 Ohm resistor is connected across the terminals then 1/2 Amp will flow (2/1+3 = 1/2)BUT 3/4 of the 2 Volts - ie 1.5 Volts - will appear at the terminals of the source.
I think this is what you are on about! Try it with other voltages and internal resistances.
RoyS.

Answer 2

Every electrical circuit has a voltage source (potential difference).
Adding elements to the circuit will introduce voltage drop - meaning that some of the initial potential will be consumed by each device in the loop.
The current in the loop is defined as the TOTAL INITIAL POTENTIAL divided by the EQUIVALENT RESISTANCE of the circuit.

Adding a resistive element (like a light bulb) to a circuit will NOT increase the voltage available to the circuit. There WILL be a voltage drop associated with the device (bulb) that can be measured ... it is probably higher than the wire that used to bridge that particular gap because the resistance of the bulb is more than the resistance of the wire.

Answer 3

Ohm's law states that, in an electrical circuit, the current passing through a conductor, from one terminal point on the conductor to another terminal point on the conductor, is directly proportional to the potential difference (i.e. voltage drop or voltage) across the two terminal points and inversely proportional to the resistance of the conductor between the two terminal points.

I = V / R where I is the current, V is the potential difference, and R is the resistance.

So, if the resistance (R) increases, the potential difference (V) decreases.

Answer 4

Bulbs add to the resistance in the circuit. If the remains steady, then the voltage will increase.

V = I*R

Answer 5

Coil resistance