find a counter example to prove ths statement false.?

Question

[x+y]=[x]+[y] th rackets are absolute value. I dont know how o insert the right symbol

sorry about the spelling misstakes... this keyboad is very old

Answer 1

The vertical bar symbol is right next to the brackets on your computer, directly above the ENTER key.

| -1 + 1 | = | 0 | = 0 and | -1 | + | 1 | = 1 + 1 = 2,
so | -1 + 1 | is not equal to | -1 | + | 1 |

Answer 2

i'll supply this a try: a million. all integers are rational numbers. real 2. each assorted of three is straightforward. pretend info: let n = a good integer 3*n is a good form (multiples of even numbers are even) 3. no helpful form is below its absolute value. real 4. no nagative form is below its absolute value. pretend. A adverse form is continuously below its absolute value. info: let x = a favorable # (for this reason -x = a adverse #) |-x| < x divide each area by way of x |-a million| < a million a million < a million it really is pretend

Answer 3

L.H.S = [ x + y] ....Consider x= 5 and y = -3 ......so ...
L.h.s = [ 5 +(-3)] = [ 5-3] = [2] =2

R.h.s = [x] + [y] = [5] + [-3] = 5 + 3 = 8
(Absolute value of -ve no. is +ve)

So, L.h.s is not equal to R.h.s ...
Hence the above statement is false .....

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