if i have 3 series circuits all with an ammeter and a voltmeter over the bulbs. in the 1st circuit there is 1 bulb , in the 2nd there are 2 and in the 3rd there are 3 bulbs.
as i added more bulbs to the circuits the resistances incresed why is that?
2007-01-11 05:33:04 · 10 answers · asked by vampire_kirstyseaden 1 in Science & Mathematics ➔ Other - Science
1) Measure the current between the voltage source and the first bulb. Measure the voltages across each bulb. You can now calculate the resistance of each bulb - if they are different - (V/I =R). the current drop at each bulb (resistance) will be in proportion to that voltage.
2) Now add the resistances together.
Rather obviously the more bulbs in series the higher the total resistance.
RoyS
2007-01-11 21:17:26 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The electrical resistance of a conductor is a measure of how difficult it is to push the charges along. You can consider the bulb as a resistor.
You have a series circuit in which the bulbs are arranged in a chain, so the current has only one path to take. The current is the same through each resistor. The total resistance of the circuit is found by simply adding up the resistance values of the individual resistors:
In this case, the equivalent resistance of resistors in series : R = R1 + R2 + R3.
So, the more bulbs you have, the circuit resistance will increase.
2007-01-11 14:00:17 · answer #2 · answered by Tarra 1 · 1⤊ 0⤋
its because all the bulbs are connected in series circuit.
the resistance for series is given as R=R1+R2
so if u go on increasing the bulbs the resistance also increases.
for eg let resistance of 1st and 2nd bulb be 2ohms and 5ohms.then resistance will be=2+3=5 ohms but if u add one more bulb with resistance say 2ohms then total resistance will be R=2+3+2=7ohms
so u see resistance goes on increasing
2007-01-11 13:46:27 · answer #3 · answered by araamdude 1 · 1⤊ 0⤋
The rule is that the resistance of a series circuit is the sum of all resistances in the series.
2007-01-11 13:43:26 · answer #4 · answered by J C 5 · 0⤊ 0⤋
Resistances in series always add together to give a higher (total) resistance (imagine that the current has to go through all of them, one after the other, so they add up.
Resistances in parallel will give less total resistance, as the current has more ways to get through.
Hope this helps.
2007-01-11 13:39:43 · answer #5 · answered by Anonymous · 0⤊ 1⤋
more bulbs create more resistance for the current to travel through.
2007-01-11 14:01:08 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Google Ohms Law
2007-01-11 13:41:09 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Consider resistances R1, R2, R3, R4,.......Rn
R1 and R2 in series gives a total restance of R = R1 + R2
Similarly R1,R2 and R3 in series will give a total resistance of R = R1 + R2 + R3.
R1,R2,R3.......... Rn in series will give a total of R = R1 + R2 + R3 + -------Rn
This shows that as you add resistances (bulbs), the total resistance ,R,is increased.
2007-01-12 09:43:48 · answer #8 · answered by Como 7 · 0⤊ 0⤋
because the electicity has more wire/filament to pass through, hence more resistance. like in Karate Kid 2, chopping through a block of ice - easy. add more blocks - more difficult.
2007-01-11 13:37:22 · answer #9 · answered by Fitz 3 · 0⤊ 0⤋
because there are more bulbs to power
2007-01-11 13:37:12 · answer #10 · answered by Anonymous · 0⤊ 0⤋